Optimal. Leaf size=476 \[ -\frac{4 c^{5/4} \left (\sqrt{c}+\sqrt{d} x\right ) \sqrt{\frac{c+d x^2}{\left (\sqrt{c}+\sqrt{d} x\right )^2}} \left (3 b^2 c^2-13 a d (9 a d+2 b c)\right ) \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right ),\frac{1}{2}\right )}{195 d^{7/4} e^{3/2} \sqrt{c+d x^2}}-\frac{2 a^2 \left (c+d x^2\right )^{5/2}}{c e \sqrt{e x}}-\frac{8 c \sqrt{e x} \sqrt{c+d x^2} \left (3 b^2 c^2-13 a d (9 a d+2 b c)\right )}{195 d^{3/2} e^2 \left (\sqrt{c}+\sqrt{d} x\right )}+\frac{8 c^{5/4} \left (\sqrt{c}+\sqrt{d} x\right ) \sqrt{\frac{c+d x^2}{\left (\sqrt{c}+\sqrt{d} x\right )^2}} \left (3 b^2 c^2-13 a d (9 a d+2 b c)\right ) E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )|\frac{1}{2}\right )}{195 d^{7/4} e^{3/2} \sqrt{c+d x^2}}-\frac{2 (e x)^{3/2} \left (c+d x^2\right )^{3/2} \left (3 b^2 c^2-13 a d (9 a d+2 b c)\right )}{117 c d e^3}-\frac{4 (e x)^{3/2} \sqrt{c+d x^2} \left (3 b^2 c^2-13 a d (9 a d+2 b c)\right )}{195 d e^3}+\frac{2 b^2 (e x)^{3/2} \left (c+d x^2\right )^{5/2}}{13 d e^3} \]
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Rubi [A] time = 0.453706, antiderivative size = 476, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {462, 459, 279, 329, 305, 220, 1196} \[ -\frac{2 a^2 \left (c+d x^2\right )^{5/2}}{c e \sqrt{e x}}-\frac{8 c \sqrt{e x} \sqrt{c+d x^2} \left (3 b^2 c^2-13 a d (9 a d+2 b c)\right )}{195 d^{3/2} e^2 \left (\sqrt{c}+\sqrt{d} x\right )}-\frac{4 c^{5/4} \left (\sqrt{c}+\sqrt{d} x\right ) \sqrt{\frac{c+d x^2}{\left (\sqrt{c}+\sqrt{d} x\right )^2}} \left (3 b^2 c^2-13 a d (9 a d+2 b c)\right ) F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )|\frac{1}{2}\right )}{195 d^{7/4} e^{3/2} \sqrt{c+d x^2}}+\frac{8 c^{5/4} \left (\sqrt{c}+\sqrt{d} x\right ) \sqrt{\frac{c+d x^2}{\left (\sqrt{c}+\sqrt{d} x\right )^2}} \left (3 b^2 c^2-13 a d (9 a d+2 b c)\right ) E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )|\frac{1}{2}\right )}{195 d^{7/4} e^{3/2} \sqrt{c+d x^2}}-\frac{2 (e x)^{3/2} \left (c+d x^2\right )^{3/2} \left (3 b^2 c^2-13 a d (9 a d+2 b c)\right )}{117 c d e^3}-\frac{4 (e x)^{3/2} \sqrt{c+d x^2} \left (3 b^2 c^2-13 a d (9 a d+2 b c)\right )}{195 d e^3}+\frac{2 b^2 (e x)^{3/2} \left (c+d x^2\right )^{5/2}}{13 d e^3} \]
Antiderivative was successfully verified.
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Rule 462
Rule 459
Rule 279
Rule 329
Rule 305
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int \frac{\left (a+b x^2\right )^2 \left (c+d x^2\right )^{3/2}}{(e x)^{3/2}} \, dx &=-\frac{2 a^2 \left (c+d x^2\right )^{5/2}}{c e \sqrt{e x}}+\frac{2 \int \sqrt{e x} \left (\frac{1}{2} a (2 b c+9 a d)+\frac{1}{2} b^2 c x^2\right ) \left (c+d x^2\right )^{3/2} \, dx}{c e^2}\\ &=-\frac{2 a^2 \left (c+d x^2\right )^{5/2}}{c e \sqrt{e x}}+\frac{2 b^2 (e x)^{3/2} \left (c+d x^2\right )^{5/2}}{13 d e^3}-\frac{\left (4 \left (\frac{3 b^2 c^2}{4}-\frac{13}{4} a d (2 b c+9 a d)\right )\right ) \int \sqrt{e x} \left (c+d x^2\right )^{3/2} \, dx}{13 c d e^2}\\ &=-\frac{2 \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right ) (e x)^{3/2} \left (c+d x^2\right )^{3/2}}{117 c d e^3}-\frac{2 a^2 \left (c+d x^2\right )^{5/2}}{c e \sqrt{e x}}+\frac{2 b^2 (e x)^{3/2} \left (c+d x^2\right )^{5/2}}{13 d e^3}-\frac{\left (2 \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right )\right ) \int \sqrt{e x} \sqrt{c+d x^2} \, dx}{39 d e^2}\\ &=-\frac{4 \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right ) (e x)^{3/2} \sqrt{c+d x^2}}{195 d e^3}-\frac{2 \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right ) (e x)^{3/2} \left (c+d x^2\right )^{3/2}}{117 c d e^3}-\frac{2 a^2 \left (c+d x^2\right )^{5/2}}{c e \sqrt{e x}}+\frac{2 b^2 (e x)^{3/2} \left (c+d x^2\right )^{5/2}}{13 d e^3}-\frac{\left (4 c \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right )\right ) \int \frac{\sqrt{e x}}{\sqrt{c+d x^2}} \, dx}{195 d e^2}\\ &=-\frac{4 \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right ) (e x)^{3/2} \sqrt{c+d x^2}}{195 d e^3}-\frac{2 \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right ) (e x)^{3/2} \left (c+d x^2\right )^{3/2}}{117 c d e^3}-\frac{2 a^2 \left (c+d x^2\right )^{5/2}}{c e \sqrt{e x}}+\frac{2 b^2 (e x)^{3/2} \left (c+d x^2\right )^{5/2}}{13 d e^3}-\frac{\left (8 c \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right )\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{c+\frac{d x^4}{e^2}}} \, dx,x,\sqrt{e x}\right )}{195 d e^3}\\ &=-\frac{4 \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right ) (e x)^{3/2} \sqrt{c+d x^2}}{195 d e^3}-\frac{2 \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right ) (e x)^{3/2} \left (c+d x^2\right )^{3/2}}{117 c d e^3}-\frac{2 a^2 \left (c+d x^2\right )^{5/2}}{c e \sqrt{e x}}+\frac{2 b^2 (e x)^{3/2} \left (c+d x^2\right )^{5/2}}{13 d e^3}-\frac{\left (8 c^{3/2} \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c+\frac{d x^4}{e^2}}} \, dx,x,\sqrt{e x}\right )}{195 d^{3/2} e^2}+\frac{\left (8 c^{3/2} \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right )\right ) \operatorname{Subst}\left (\int \frac{1-\frac{\sqrt{d} x^2}{\sqrt{c} e}}{\sqrt{c+\frac{d x^4}{e^2}}} \, dx,x,\sqrt{e x}\right )}{195 d^{3/2} e^2}\\ &=-\frac{4 \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right ) (e x)^{3/2} \sqrt{c+d x^2}}{195 d e^3}-\frac{8 c \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right ) \sqrt{e x} \sqrt{c+d x^2}}{195 d^{3/2} e^2 \left (\sqrt{c}+\sqrt{d} x\right )}-\frac{2 \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right ) (e x)^{3/2} \left (c+d x^2\right )^{3/2}}{117 c d e^3}-\frac{2 a^2 \left (c+d x^2\right )^{5/2}}{c e \sqrt{e x}}+\frac{2 b^2 (e x)^{3/2} \left (c+d x^2\right )^{5/2}}{13 d e^3}+\frac{8 c^{5/4} \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right ) \left (\sqrt{c}+\sqrt{d} x\right ) \sqrt{\frac{c+d x^2}{\left (\sqrt{c}+\sqrt{d} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )|\frac{1}{2}\right )}{195 d^{7/4} e^{3/2} \sqrt{c+d x^2}}-\frac{4 c^{5/4} \left (3 b^2 c^2-13 a d (2 b c+9 a d)\right ) \left (\sqrt{c}+\sqrt{d} x\right ) \sqrt{\frac{c+d x^2}{\left (\sqrt{c}+\sqrt{d} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{d} \sqrt{e x}}{\sqrt [4]{c} \sqrt{e}}\right )|\frac{1}{2}\right )}{195 d^{7/4} e^{3/2} \sqrt{c+d x^2}}\\ \end{align*}
Mathematica [C] time = 0.145505, size = 161, normalized size = 0.34 \[ \frac{x \left (24 c x^2 \sqrt{\frac{c}{d x^2}+1} \left (117 a^2 d^2+26 a b c d-3 b^2 c^2\right ) \, _2F_1\left (-\frac{1}{4},\frac{1}{2};\frac{3}{4};-\frac{c}{d x^2}\right )+2 \left (c+d x^2\right ) \left (117 a^2 d \left (d x^2-5 c\right )+26 a b d x^2 \left (11 c+5 d x^2\right )+3 b^2 x^2 \left (4 c^2+25 c d x^2+15 d^2 x^4\right )\right )\right )}{585 d (e x)^{3/2} \sqrt{c+d x^2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.02, size = 669, normalized size = 1.4 \begin{align*}{\frac{2}{585\,e{d}^{2}} \left ( 45\,{x}^{8}{b}^{2}{d}^{4}+130\,{x}^{6}ab{d}^{4}+120\,{x}^{6}{b}^{2}c{d}^{3}+1404\,\sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{2}\sqrt{{\frac{-dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{-{\frac{dx}{\sqrt{-cd}}}}{\it EllipticE} \left ( \sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}},1/2\,\sqrt{2} \right ){a}^{2}{c}^{2}{d}^{2}+312\,\sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{2}\sqrt{{\frac{-dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{-{\frac{dx}{\sqrt{-cd}}}}{\it EllipticE} \left ( \sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}},1/2\,\sqrt{2} \right ) ab{c}^{3}d-36\,\sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{2}\sqrt{{\frac{-dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{-{\frac{dx}{\sqrt{-cd}}}}{\it EllipticE} \left ( \sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}},1/2\,\sqrt{2} \right ){b}^{2}{c}^{4}-702\,\sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{2}\sqrt{{\frac{-dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{-{\frac{dx}{\sqrt{-cd}}}}{\it EllipticF} \left ( \sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}},1/2\,\sqrt{2} \right ){a}^{2}{c}^{2}{d}^{2}-156\,\sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{2}\sqrt{{\frac{-dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{-{\frac{dx}{\sqrt{-cd}}}}{\it EllipticF} \left ( \sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}},1/2\,\sqrt{2} \right ) ab{c}^{3}d+18\,\sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{2}\sqrt{{\frac{-dx+\sqrt{-cd}}{\sqrt{-cd}}}}\sqrt{-{\frac{dx}{\sqrt{-cd}}}}{\it EllipticF} \left ( \sqrt{{\frac{dx+\sqrt{-cd}}{\sqrt{-cd}}}},1/2\,\sqrt{2} \right ){b}^{2}{c}^{4}+117\,{x}^{4}{a}^{2}{d}^{4}+416\,{x}^{4}abc{d}^{3}+87\,{x}^{4}{b}^{2}{c}^{2}{d}^{2}-468\,{x}^{2}{a}^{2}c{d}^{3}+286\,{x}^{2}ab{c}^{2}{d}^{2}+12\,{x}^{2}{b}^{2}{c}^{3}d-585\,{a}^{2}{c}^{2}{d}^{2} \right ){\frac{1}{\sqrt{d{x}^{2}+c}}}{\frac{1}{\sqrt{ex}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x^{2} + a\right )}^{2}{\left (d x^{2} + c\right )}^{\frac{3}{2}}}{\left (e x\right )^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (b^{2} d x^{6} +{\left (b^{2} c + 2 \, a b d\right )} x^{4} + a^{2} c +{\left (2 \, a b c + a^{2} d\right )} x^{2}\right )} \sqrt{d x^{2} + c} \sqrt{e x}}{e^{2} x^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 35.2059, size = 309, normalized size = 0.65 \begin{align*} \frac{a^{2} c^{\frac{3}{2}} \Gamma \left (- \frac{1}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, - \frac{1}{4} \\ \frac{3}{4} \end{matrix}\middle |{\frac{d x^{2} e^{i \pi }}{c}} \right )}}{2 e^{\frac{3}{2}} \sqrt{x} \Gamma \left (\frac{3}{4}\right )} + \frac{a^{2} \sqrt{c} d x^{\frac{3}{2}} \Gamma \left (\frac{3}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{3}{4} \\ \frac{7}{4} \end{matrix}\middle |{\frac{d x^{2} e^{i \pi }}{c}} \right )}}{2 e^{\frac{3}{2}} \Gamma \left (\frac{7}{4}\right )} + \frac{a b c^{\frac{3}{2}} x^{\frac{3}{2}} \Gamma \left (\frac{3}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{3}{4} \\ \frac{7}{4} \end{matrix}\middle |{\frac{d x^{2} e^{i \pi }}{c}} \right )}}{e^{\frac{3}{2}} \Gamma \left (\frac{7}{4}\right )} + \frac{a b \sqrt{c} d x^{\frac{7}{2}} \Gamma \left (\frac{7}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{7}{4} \\ \frac{11}{4} \end{matrix}\middle |{\frac{d x^{2} e^{i \pi }}{c}} \right )}}{e^{\frac{3}{2}} \Gamma \left (\frac{11}{4}\right )} + \frac{b^{2} c^{\frac{3}{2}} x^{\frac{7}{2}} \Gamma \left (\frac{7}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{7}{4} \\ \frac{11}{4} \end{matrix}\middle |{\frac{d x^{2} e^{i \pi }}{c}} \right )}}{2 e^{\frac{3}{2}} \Gamma \left (\frac{11}{4}\right )} + \frac{b^{2} \sqrt{c} d x^{\frac{11}{2}} \Gamma \left (\frac{11}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{11}{4} \\ \frac{15}{4} \end{matrix}\middle |{\frac{d x^{2} e^{i \pi }}{c}} \right )}}{2 e^{\frac{3}{2}} \Gamma \left (\frac{15}{4}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x^{2} + a\right )}^{2}{\left (d x^{2} + c\right )}^{\frac{3}{2}}}{\left (e x\right )^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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